Comments on: Tips for Manipulating dates in MySQL. http://www.wiseguysonly.com/2009/02/06/tips-for-manipulating-dates-in-mysql/ PHP,MySQL and jQuery Developer Tue, 20 Jul 2010 13:13:48 +0200 http://wordpress.org/?v=2.8.4 hourly 1 By: dinesh http://www.wiseguysonly.com/2009/02/06/tips-for-manipulating-dates-in-mysql/comment-page-1/#comment-5747 dinesh Fri, 09 Jul 2010 13:50:32 +0000 http://www.wiseguysonly.com/?p=197#comment-5747 Wonder if you can help me with formating a date using a mysql_fetch_array. Following your instructions above and am to MySQL & PHP . I get a “supplied argument is not a valid MySQL result resource error” and I think that I am not getting the right syntax. I have field joindate which is saved as now() and I endeavouring to change it to %a %d %b %Y. Here is the code: $list_count = mysql_fetch_array(mysql_query(”SELECT COUNT(*) FROM $list WHERE userid=’$f[id]‘,DATE_FORMAT(NOW(),’%a %d %b %Y’) as joindate;” )); Appreciate your help Wonder if you can help me with formating a date using a mysql_fetch_array. Following your instructions above and am to MySQL & PHP . I get a “supplied argument is not a valid MySQL result resource error” and I think that I am not getting the right syntax.
I have field joindate which is saved as now() and I endeavouring to change it to %a %d %b %Y. Here is the code:
$list_count = mysql_fetch_array(mysql_query(”SELECT COUNT(*) FROM $list WHERE userid=’$f[id]‘,DATE_FORMAT(NOW(),’%a %d %b %Y’) as joindate;” ));

Appreciate your help

]]> By: Jean http://www.wiseguysonly.com/2009/02/06/tips-for-manipulating-dates-in-mysql/comment-page-1/#comment-4647 Jean Thu, 25 Jun 2009 12:23:35 +0000 http://www.wiseguysonly.com/?p=197#comment-4647 Hi Wonder if you can help me with formating a date using a mysql_fetch_array. Following your instructions above and am to MySQL & PHP . I get a "supplied argument is not a valid MySQL result resource error" and I think that I am not getting the right syntax. I have field joindate which is saved as now() and I endeavouring to change it to %a %d %b %Y. Here is the code: $list_count = mysql_fetch_array(mysql_query("SELECT COUNT(*) FROM $list WHERE userid='$f[id]',DATE_FORMAT(NOW(),’%a %d %b %Y’) as joindate;" )); Appreciate your help Hi
Wonder if you can help me with formating a date using a mysql_fetch_array. Following your instructions above and am to MySQL & PHP . I get a “supplied argument is not a valid MySQL result resource error” and I think that I am not getting the right syntax.
I have field joindate which is saved as now() and I endeavouring to change it to %a %d %b %Y. Here is the code:
$list_count = mysql_fetch_array(mysql_query(”SELECT COUNT(*) FROM $list WHERE userid=’$f[id]‘,DATE_FORMAT(NOW(),’%a %d %b %Y’) as joindate;” ));

Appreciate your help

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